2^2+28=x^2+11x

Solution for 2^2+28=x^2+11x equation:

2^2+28=x^2+11x

We move all terms to the left:

2^2+28-(x^2+11x)=0

We add all the numbers together, and all the variables

-(x^2+11x)+32=0

We get rid of parentheses

-x^2-11x+32=0

We add all the numbers together, and all the variables

-1x^2-11x+32=0

a = -1; b = -11; c = +32;
Δ = b2-4ac
Δ = -112-4·(-1)·32
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{249}}{2*-1}=\frac{11-\sqrt{249}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{249}}{2*-1}=\frac{11+\sqrt{249}}{-2}
$